4(x+3)=8(x-1)

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Solution for 4(x+3)=8(x-1) equation: 



4(x+3)=8(x-1)

We move all terms to the left:

4(x+3)-(8(x-1))=0

We multiply parentheses

4x-(8(x-1))+12=0



We calculate terms in parentheses: -(8(x-1)), so:

8(x-1)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We get rid of parentheses

4x-8x+8+12=0

We add all the numbers together, and all the variables

-4x+20=0

We move all terms containing x to the left, all other terms to the right

-4x=-20

x=-20/-4

x=+5

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