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4(x+3)=x+
We move all terms to the left:
4(x+3)-(x+)=0
We add all the numbers together, and all the variables
4(x+3)-(+x)=0
We multiply parentheses
4x-(+x)+12=0
We get rid of parentheses
4x-x+12=0
We add all the numbers together, and all the variables
3x+12=0
We move all terms containing x to the left, all other terms to the right
3x=-12
x=-12/3
x=-4
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