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4(x+3)=x+12+3x
We move all terms to the left:
4(x+3)-(x+12+3x)=0
We add all the numbers together, and all the variables
4(x+3)-(4x+12)=0
We multiply parentheses
4x-(4x+12)+12=0
We get rid of parentheses
4x-4x-12+12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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