4(x+3/2)-5=10

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Solution for 4(x+3/2)-5=10 equation: 



4(x+3/2)-5=10

We move all terms to the left:

4(x+3/2)-5-(10)=0

We add all the numbers together, and all the variables

4(+x+3/2)-5-10=0

We add all the numbers together, and all the variables

4(+x+3/2)-15=0

We multiply parentheses

4x-15+3/2*4=0

We multiply all the terms by the denominator


4x*2*4+3-15*2*4=0

We add all the numbers together, and all the variables

4x*2*4-117=0

Wy multiply elements

32x*4-117=0

Wy multiply elements

128x-117=0

We move all terms containing x to the left, all other terms to the right

128x=117

x=117/128

x=117/128

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