4(x+4)+3(x-3)=2(x-3)+12

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Solution for 4(x+4)+3(x-3)=2(x-3)+12 equation: 



4(x+4)+3(x-3)=2(x-3)+12

We move all terms to the left:

4(x+4)+3(x-3)-(2(x-3)+12)=0

We multiply parentheses

4x+3x-(2(x-3)+12)+16-9=0



We calculate terms in parentheses: -(2(x-3)+12), so:

2(x-3)+12

We multiply parentheses

2x-6+12

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

7x-(2x+6)+7=0

We get rid of parentheses

7x-2x-6+7=0

We add all the numbers together, and all the variables

5x+1=0

We move all terms containing x to the left, all other terms to the right

5x=-1

x=-1/5

x=-1/5

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