4(x+4)+3=7x+4(x+3)

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Solution for 4(x+4)+3=7x+4(x+3) equation: 



4(x+4)+3=7x+4(x+3)

We move all terms to the left:

4(x+4)+3-(7x+4(x+3))=0

We multiply parentheses

4x-(7x+4(x+3))+16+3=0



We calculate terms in parentheses: -(7x+4(x+3)), so:

7x+4(x+3)

We multiply parentheses

7x+4x+12

We add all the numbers together, and all the variables

11x+12

Back to the equation:

-(11x+12)



We add all the numbers together, and all the variables

4x-(11x+12)+19=0

We get rid of parentheses

4x-11x-12+19=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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