4(x+4)=-2(8x-6)+8x

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Solution for 4(x+4)=-2(8x-6)+8x equation: 



4(x+4)=-2(8x-6)+8x

We move all terms to the left:

4(x+4)-(-2(8x-6)+8x)=0

We multiply parentheses

4x-(-2(8x-6)+8x)+16=0



We calculate terms in parentheses: -(-2(8x-6)+8x), so:

-2(8x-6)+8x

We add all the numbers together, and all the variables

8x-2(8x-6)

We multiply parentheses

8x-16x+12

We add all the numbers together, and all the variables

-8x+12

Back to the equation:

-(-8x+12)



We get rid of parentheses

4x+8x-12+16=0

We add all the numbers together, and all the variables

12x+4=0

We move all terms containing x to the left, all other terms to the right

12x=-4

x=-4/12

x=-1/3

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