4(x+4)=3x+12

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Solution for 4(x+4)=3x+12 equation: 



4(x+4)=3x+12

We move all terms to the left:

4(x+4)-(3x+12)=0

We multiply parentheses

4x-(3x+12)+16=0

We get rid of parentheses

4x-3x-12+16=0

We add all the numbers together, and all the variables

x+4=0

We move all terms containing x to the left, all other terms to the right

x=-4

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