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4(x+4)=54-(x-5)
We move all terms to the left:
4(x+4)-(54-(x-5))=0
We multiply parentheses
4x-(54-(x-5))+16=0
We calculate terms in parentheses: -(54-(x-5)), so:We get rid of parentheses
54-(x-5)
determiningTheFunctionDomain -(x-5)+54
We get rid of parentheses
-x+5+54
We add all the numbers together, and all the variables
-1x+59
Back to the equation:
-(-1x+59)
4x+1x-59+16=0
We add all the numbers together, and all the variables
5x-43=0
We move all terms containing x to the left, all other terms to the right
5x=43
x=43/5
x=8+3/5
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