4(x+4)=7+3x+54(x+4)=7+3x+5

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Solution for 4(x+4)=7+3x+54(x+4)=7+3x+5 equation: 



4(x+4)=7+3x+54(x+4)=7+3x+5

We move all terms to the left:

4(x+4)-(7+3x+54(x+4))=0

We multiply parentheses

4x-(7+3x+54(x+4))+16=0



We calculate terms in parentheses: -(7+3x+54(x+4)), so:

7+3x+54(x+4)

determiningTheFunctionDomain
3x+54(x+4)+7

We multiply parentheses

3x+54x+216+7

We add all the numbers together, and all the variables

57x+223

Back to the equation:

-(57x+223)



We get rid of parentheses

4x-57x-223+16=0

We add all the numbers together, and all the variables

-53x-207=0

We move all terms containing x to the left, all other terms to the right

-53x=207

x=207/-53

x=-3+48/53

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