4(x+40)=2(x-3)

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Solution for 4(x+40)=2(x-3) equation: 



4(x+40)=2(x-3)

We move all terms to the left:

4(x+40)-(2(x-3))=0

We multiply parentheses

4x-(2(x-3))+160=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

4x-2x+6+160=0

We add all the numbers together, and all the variables

2x+166=0

We move all terms containing x to the left, all other terms to the right

2x=-166

x=-166/2

x=-83

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