4(x+5)-(4x-3)=3(3x+2)-28

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Solution for 4(x+5)-(4x-3)=3(3x+2)-28 equation: 



4(x+5)-(4x-3)=3(3x+2)-28

We move all terms to the left:

4(x+5)-(4x-3)-(3(3x+2)-28)=0

We multiply parentheses

4x-(4x-3)-(3(3x+2)-28)+20=0

We get rid of parentheses

4x-4x-(3(3x+2)-28)+3+20=0



We calculate terms in parentheses: -(3(3x+2)-28), so:

3(3x+2)-28

We multiply parentheses

9x+6-28

We add all the numbers together, and all the variables

9x-22

Back to the equation:

-(9x-22)



We add all the numbers together, and all the variables

-(9x-22)+23=0

We get rid of parentheses

-9x+22+23=0

We add all the numbers together, and all the variables

-9x+45=0

We move all terms containing x to the left, all other terms to the right

-9x=-45

x=-45/-9

x=+5

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