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4(x+5)-3=12-6(2x-4)
We move all terms to the left:
4(x+5)-3-(12-6(2x-4))=0
We multiply parentheses
4x-(12-6(2x-4))+20-3=0
We calculate terms in parentheses: -(12-6(2x-4)), so:We add all the numbers together, and all the variables
12-6(2x-4)
determiningTheFunctionDomain -6(2x-4)+12
We multiply parentheses
-12x+24+12
We add all the numbers together, and all the variables
-12x+36
Back to the equation:
-(-12x+36)
4x-(-12x+36)+17=0
We get rid of parentheses
4x+12x-36+17=0
We add all the numbers together, and all the variables
16x-19=0
We move all terms containing x to the left, all other terms to the right
16x=19
x=19/16
x=1+3/16
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