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4(x+5)=2(10+2x)
We move all terms to the left:
4(x+5)-(2(10+2x))=0
We add all the numbers together, and all the variables
4(x+5)-(2(2x+10))=0
We multiply parentheses
4x-(2(2x+10))+20=0
We calculate terms in parentheses: -(2(2x+10)), so:We get rid of parentheses
2(2x+10)
We multiply parentheses
4x+20
Back to the equation:
-(4x+20)
4x-4x-20+20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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