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4(x+5)=3(x+2)
We move all terms to the left:
4(x+5)-(3(x+2))=0
We multiply parentheses
4x-(3(x+2))+20=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
4x-3x-6+20=0
We add all the numbers together, and all the variables
x+14=0
We move all terms containing x to the left, all other terms to the right
x=-14
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