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4(x+5)=3(x-5)+x
We move all terms to the left:
4(x+5)-(3(x-5)+x)=0
We multiply parentheses
4x-(3(x-5)+x)+20=0
We calculate terms in parentheses: -(3(x-5)+x), so:We get rid of parentheses
3(x-5)+x
We add all the numbers together, and all the variables
x+3(x-5)
We multiply parentheses
x+3x-15
We add all the numbers together, and all the variables
4x-15
Back to the equation:
-(4x-15)
4x-4x+15+20=0
We add all the numbers together, and all the variables
35!=0
There is no solution for this equation
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