4(x+5)=32-2x

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Solution for 4(x+5)=32-2x equation: 



4(x+5)=32-2x

We move all terms to the left:

4(x+5)-(32-2x)=0

We add all the numbers together, and all the variables

4(x+5)-(-2x+32)=0

We multiply parentheses

4x-(-2x+32)+20=0

We get rid of parentheses

4x+2x-32+20=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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