4(x+5)=7x+47

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Solution for 4(x+5)=7x+47 equation: 



4(x+5)=7x+47

We move all terms to the left:

4(x+5)-(7x+47)=0

We multiply parentheses

4x-(7x+47)+20=0

We get rid of parentheses

4x-7x-47+20=0

We add all the numbers together, and all the variables

-3x-27=0

We move all terms containing x to the left, all other terms to the right

-3x=27

x=27/-3

x=-9

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