4(x+5x)=16x+56-4(2x-1)

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Solution for 4(x+5x)=16x+56-4(2x-1) equation: 



4(x+5x)=16x+56-4(2x-1)

We move all terms to the left:

4(x+5x)-(16x+56-4(2x-1))=0

We add all the numbers together, and all the variables

4(+6x)-(16x+56-4(2x-1))=0

We multiply parentheses

24x-(16x+56-4(2x-1))=0



We calculate terms in parentheses: -(16x+56-4(2x-1)), so:

16x+56-4(2x-1)

determiningTheFunctionDomain
16x-4(2x-1)+56

We multiply parentheses

16x-8x+4+56

We add all the numbers together, and all the variables

8x+60

Back to the equation:

-(8x+60)



We get rid of parentheses

24x-8x-60=0

We add all the numbers together, and all the variables

16x-60=0

We move all terms containing x to the left, all other terms to the right

16x=60

x=60/16

x=3+3/4

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