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4(x+6)(2x-3)=0
We multiply parentheses ..
4(+2x^2-3x+12x-18)=0
We multiply parentheses
8x^2-12x+48x-72=0
We add all the numbers together, and all the variables
8x^2+36x-72=0
a = 8; b = 36; c = -72;
Δ = b2-4ac
Δ = 362-4·8·(-72)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-60}{2*8}=\frac{-96}{16} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+60}{2*8}=\frac{24}{16} =1+1/2 $
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