4(x+7)-20=5x+3x2x

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Solution for 4(x+7)-20=5x+3x2x equation: 



4(x+7)-20=5x+3x^2x

We move all terms to the left:

4(x+7)-20-(5x+3x^2x)=0

We multiply parentheses

-(5x+3x^2x)+4x+28-20=0

We get rid of parentheses

-3x^2x-5x+4x+28-20=0

We add all the numbers together, and all the variables

-3x^2x-1x+8=0

We move all terms containing x to the left, all other terms to the right

-3x^2x-1x=-8

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