4(x+8)=-6(3x-5)+6x

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Solution for 4(x+8)=-6(3x-5)+6x equation: 



4(x+8)=-6(3x-5)+6x

We move all terms to the left:

4(x+8)-(-6(3x-5)+6x)=0

We multiply parentheses

4x-(-6(3x-5)+6x)+32=0



We calculate terms in parentheses: -(-6(3x-5)+6x), so:

-6(3x-5)+6x

We add all the numbers together, and all the variables

6x-6(3x-5)

We multiply parentheses

6x-18x+30

We add all the numbers together, and all the variables

-12x+30

Back to the equation:

-(-12x+30)



We get rid of parentheses

4x+12x-30+32=0

We add all the numbers together, and all the variables

16x+2=0

We move all terms containing x to the left, all other terms to the right

16x=-2

x=-2/16

x=-1/8

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