4(x-(3-2x))+8=12(x+3)

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Solution for 4(x-(3-2x))+8=12(x+3) equation: 



4(x-(3-2x))+8=12(x+3)

We move all terms to the left:

4(x-(3-2x))+8-(12(x+3))=0

We add all the numbers together, and all the variables

4(x-(-2x+3))-(12(x+3))+8=0



We calculate terms in parentheses: -(12(x+3)), so:

12(x+3)

We multiply parentheses

12x+36

Back to the equation:

-(12x+36)



We get rid of parentheses

4(x-(-2x+3))-12x-36+8=0

We add all the numbers together, and all the variables

-12x+4(x-(-2x+3))-28=0

We move all terms containing x to the left, all other terms to the right

-12x+4(x-(-2x+3))=28

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