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4(x-1)+10=3(2x-2)
We move all terms to the left:
4(x-1)+10-(3(2x-2))=0
We multiply parentheses
4x-(3(2x-2))-4+10=0
We calculate terms in parentheses: -(3(2x-2)), so:We add all the numbers together, and all the variables
3(2x-2)
We multiply parentheses
6x-6
Back to the equation:
-(6x-6)
4x-(6x-6)+6=0
We get rid of parentheses
4x-6x+6+6=0
We add all the numbers together, and all the variables
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6
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