4(x-1)+12=2(x+3)+10

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Solution for 4(x-1)+12=2(x+3)+10 equation: 



4(x-1)+12=2(x+3)+10

We move all terms to the left:

4(x-1)+12-(2(x+3)+10)=0

We multiply parentheses

4x-(2(x+3)+10)-4+12=0



We calculate terms in parentheses: -(2(x+3)+10), so:

2(x+3)+10

We multiply parentheses

2x+6+10

We add all the numbers together, and all the variables

2x+16

Back to the equation:

-(2x+16)



We add all the numbers together, and all the variables

4x-(2x+16)+8=0

We get rid of parentheses

4x-2x-16+8=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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