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4(x-1)+1=2x+(-1+x)
We move all terms to the left:
4(x-1)+1-(2x+(-1+x))=0
We add all the numbers together, and all the variables
4(x-1)-(2x+(x-1))+1=0
We multiply parentheses
4x-(2x+(x-1))-4+1=0
We calculate terms in parentheses: -(2x+(x-1)), so:We add all the numbers together, and all the variables
2x+(x-1)
We get rid of parentheses
2x+x-1
We add all the numbers together, and all the variables
3x-1
Back to the equation:
-(3x-1)
4x-(3x-1)-3=0
We get rid of parentheses
4x-3x+1-3=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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