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4(x-1)+2=2(x+2)+x
We move all terms to the left:
4(x-1)+2-(2(x+2)+x)=0
We multiply parentheses
4x-(2(x+2)+x)-4+2=0
We calculate terms in parentheses: -(2(x+2)+x), so:We add all the numbers together, and all the variables
2(x+2)+x
We add all the numbers together, and all the variables
x+2(x+2)
We multiply parentheses
x+2x+4
We add all the numbers together, and all the variables
3x+4
Back to the equation:
-(3x+4)
4x-(3x+4)-2=0
We get rid of parentheses
4x-3x-4-2=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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