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4(x-1)+3=6x-2(2+x)
We move all terms to the left:
4(x-1)+3-(6x-2(2+x))=0
We add all the numbers together, and all the variables
4(x-1)-(6x-2(x+2))+3=0
We multiply parentheses
4x-(6x-2(x+2))-4+3=0
We calculate terms in parentheses: -(6x-2(x+2)), so:We add all the numbers together, and all the variables
6x-2(x+2)
We multiply parentheses
6x-2x-4
We add all the numbers together, and all the variables
4x-4
Back to the equation:
-(4x-4)
4x-(4x-4)-1=0
We get rid of parentheses
4x-4x+4-1=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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