4(x-1)+3x=2(x+3)

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Solution for 4(x-1)+3x=2(x+3) equation: 



4(x-1)+3x=2(x+3)

We move all terms to the left:

4(x-1)+3x-(2(x+3))=0

We add all the numbers together, and all the variables

3x+4(x-1)-(2(x+3))=0

We multiply parentheses

3x+4x-(2(x+3))-4=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

7x-(2x+6)-4=0

We get rid of parentheses

7x-2x-6-4=0

We add all the numbers together, and all the variables

5x-10=0

We move all terms containing x to the left, all other terms to the right

5x=10

x=10/5

x=2

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