4(x-1)+3x=8-4(x-2)

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Solution for 4(x-1)+3x=8-4(x-2) equation: 



4(x-1)+3x=8-4(x-2)

We move all terms to the left:

4(x-1)+3x-(8-4(x-2))=0

We add all the numbers together, and all the variables

3x+4(x-1)-(8-4(x-2))=0

We multiply parentheses

3x+4x-(8-4(x-2))-4=0



We calculate terms in parentheses: -(8-4(x-2)), so:

8-4(x-2)

determiningTheFunctionDomain
-4(x-2)+8

We multiply parentheses

-4x+8+8

We add all the numbers together, and all the variables

-4x+16

Back to the equation:

-(-4x+16)



We add all the numbers together, and all the variables

7x-(-4x+16)-4=0

We get rid of parentheses

7x+4x-16-4=0

We add all the numbers together, and all the variables

11x-20=0

We move all terms containing x to the left, all other terms to the right

11x=20

x=20/11

x=1+9/11

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