4(x-1)+3x=8-4(x-2)

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Solution for 4(x-1)+3x=8-4(x-2) equation:



4(x-1)+3x=8-4(x-2)
We move all terms to the left:
4(x-1)+3x-(8-4(x-2))=0
We add all the numbers together, and all the variables
3x+4(x-1)-(8-4(x-2))=0
We multiply parentheses
3x+4x-(8-4(x-2))-4=0
We calculate terms in parentheses: -(8-4(x-2)), so:
8-4(x-2)
determiningTheFunctionDomain -4(x-2)+8
We multiply parentheses
-4x+8+8
We add all the numbers together, and all the variables
-4x+16
Back to the equation:
-(-4x+16)
We add all the numbers together, and all the variables
7x-(-4x+16)-4=0
We get rid of parentheses
7x+4x-16-4=0
We add all the numbers together, and all the variables
11x-20=0
We move all terms containing x to the left, all other terms to the right
11x=20
x=20/11
x=1+9/11

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