4(x-1)+5(x+2)=6(x-2)

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Solution for 4(x-1)+5(x+2)=6(x-2) equation: 



4(x-1)+5(x+2)=6(x-2)

We move all terms to the left:

4(x-1)+5(x+2)-(6(x-2))=0

We multiply parentheses

4x+5x-(6(x-2))-4+10=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

9x-(6x-12)+6=0

We get rid of parentheses

9x-6x+12+6=0

We add all the numbers together, and all the variables

3x+18=0

We move all terms containing x to the left, all other terms to the right

3x=-18

x=-18/3

x=-6

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