4(x-1)+5=6(x+2)+3

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Solution for 4(x-1)+5=6(x+2)+3 equation: 



4(x-1)+5=6(x+2)+3

We move all terms to the left:

4(x-1)+5-(6(x+2)+3)=0

We multiply parentheses

4x-(6(x+2)+3)-4+5=0



We calculate terms in parentheses: -(6(x+2)+3), so:

6(x+2)+3

We multiply parentheses

6x+12+3

We add all the numbers together, and all the variables

6x+15

Back to the equation:

-(6x+15)



We add all the numbers together, and all the variables

4x-(6x+15)+1=0

We get rid of parentheses

4x-6x-15+1=0

We add all the numbers together, and all the variables

-2x-14=0

We move all terms containing x to the left, all other terms to the right

-2x=14

x=14/-2

x=-7

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