4(x-1)-(x-2)=5(x+1)+3

Solution for 4(x-1)-(x-2)=5(x+1)+3 equation:

4(x-1)-(x-2)=5(x+1)+3

We move all terms to the left:

4(x-1)-(x-2)-(5(x+1)+3)=0

We multiply parentheses

4x-(x-2)-(5(x+1)+3)-4=0

We get rid of parentheses

4x-x-(5(x+1)+3)+2-4=0


We calculate terms in parentheses: -(5(x+1)+3), so:

5(x+1)+3

We multiply parentheses

5x+5+3

We add all the numbers together, and all the variables

5x+8

Back to the equation:

-(5x+8)


We add all the numbers together, and all the variables

3x-(5x+8)-2=0

We get rid of parentheses

3x-5x-8-2=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5