4(x-1)-3(2x+1)=5-6(-x+2)

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Solution for 4(x-1)-3(2x+1)=5-6(-x+2) equation: 



4(x-1)-3(2x+1)=5-6(-x+2)

We move all terms to the left:

4(x-1)-3(2x+1)-(5-6(-x+2))=0

We add all the numbers together, and all the variables

4(x-1)-3(2x+1)-(5-6(-1x+2))=0

We multiply parentheses

4x-6x-(5-6(-1x+2))-4-3=0



We calculate terms in parentheses: -(5-6(-1x+2)), so:

5-6(-1x+2)

determiningTheFunctionDomain
-6(-1x+2)+5

We multiply parentheses

6x-12+5

We add all the numbers together, and all the variables

6x-7

Back to the equation:

-(6x-7)



We add all the numbers together, and all the variables

-2x-(6x-7)-7=0

We get rid of parentheses

-2x-6x+7-7=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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