4(x-1)-3(x+1)=2(x+4)

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Solution for 4(x-1)-3(x+1)=2(x+4) equation: 



4(x-1)-3(x+1)=2(x+4)

We move all terms to the left:

4(x-1)-3(x+1)-(2(x+4))=0

We multiply parentheses

4x-3x-(2(x+4))-4-3=0



We calculate terms in parentheses: -(2(x+4)), so:

2(x+4)

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

x-(2x+8)-7=0

We get rid of parentheses

x-2x-8-7=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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