4(x-1)-5(20-x)=12(4-7x)-100

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Solution for 4(x-1)-5(20-x)=12(4-7x)-100 equation:



4(x-1)-5(20-x)=12(4-7x)-100
We move all terms to the left:
4(x-1)-5(20-x)-(12(4-7x)-100)=0
We add all the numbers together, and all the variables
4(x-1)-5(-1x+20)-(12(-7x+4)-100)=0
We multiply parentheses
4x+5x-(12(-7x+4)-100)-4-100=0
We calculate terms in parentheses: -(12(-7x+4)-100), so:
12(-7x+4)-100
We multiply parentheses
-84x+48-100
We add all the numbers together, and all the variables
-84x-52
Back to the equation:
-(-84x-52)
We add all the numbers together, and all the variables
9x-(-84x-52)-104=0
We get rid of parentheses
9x+84x+52-104=0
We add all the numbers together, and all the variables
93x-52=0
We move all terms containing x to the left, all other terms to the right
93x=52
x=52/93
x=52/93

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