4(x-1)/5+1+2/x

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Solution for 4(x-1)/5+1+2/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4*(x-1))/5+2/x+1 = 0

(4*x*(x-1))/(5*x)+(2*5)/(5*x)+(1*5*x)/(5*x) = 0

4*x*(x-1)+1*5*x+2*5 = 0

4*x^2-4*x+5*x+10 = 0

4*x^2+x+10 = 0

4*x^2+x+10 = 0

4*x^2+x+10 = 0

DELTA = 1^2-(4*4*10)

DELTA = -159

DELTA < 0

1 = 0

1/(5*x) = 0

1/(5*x) = 0 // * 5*x

1 = 0

x belongs to the empty set

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