4(x-1)/8=2(x+1)/6

Solution for 4(x-1)/8=2(x+1)/6 equation:

4(x-1)/8=2(x+1)/6

We move all terms to the left:

4(x-1)/8-(2(x+1)/6)=0

We calculate fractions


4x/()+(-(2(x+1)*8)/()=0


We calculate terms in parentheses: +(-(2(x+1)*8)/(), so:

-(2(x+1)*8)/(

We multiply all the terms by the denominator


-(2(x+1)*8)


We calculate terms in parentheses: -(2(x+1)*8), so:

2(x+1)*8

We multiply parentheses

16x+16

Back to the equation:

-(16x+16)


We get rid of parentheses

-16x-16

Back to the equation:

+(-16x-16)


We get rid of parentheses

4x/()-16x-16=0

We multiply all the terms by the denominator


4x-16x*()-16*()=0

We add all the numbers together, and all the variables

4x-16x*()=0