4(x-1)/8=2(x+2)/7

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Solution for 4(x-1)/8=2(x+2)/7 equation: 



4(x-1)/8=2(x+2)/7

We move all terms to the left:

4(x-1)/8-(2(x+2)/7)=0

We calculate fractions


4x/()+(-(2(x+2)*8)/()=0



We calculate terms in parentheses: +(-(2(x+2)*8)/(), so:

-(2(x+2)*8)/(

We multiply all the terms by the denominator


-(2(x+2)*8)



We calculate terms in parentheses: -(2(x+2)*8), so:

2(x+2)*8

We multiply parentheses

16x+32

Back to the equation:

-(16x+32)



We get rid of parentheses

-16x-32

Back to the equation:

+(-16x-32)



We get rid of parentheses

4x/()-16x-32=0

We multiply all the terms by the denominator


4x-16x*()-32*()=0

We add all the numbers together, and all the variables

4x-16x*()=0

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