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4(x-1)=1/4(2x)
We move all terms to the left:
4(x-1)-(1/4(2x))=0
Domain of the equation: 42x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4(x-1)-(+1/42x)=0
We multiply parentheses
4x-(+1/42x)-4=0
We get rid of parentheses
4x-1/42x-4=0
We multiply all the terms by the denominator
4x*42x-4*42x-1=0
Wy multiply elements
168x^2-168x-1=0
a = 168; b = -168; c = -1;
Δ = b2-4ac
Δ = -1682-4·168·(-1)
Δ = 28896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28896}=\sqrt{16*1806}=\sqrt{16}*\sqrt{1806}=4\sqrt{1806}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-4\sqrt{1806}}{2*168}=\frac{168-4\sqrt{1806}}{336} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+4\sqrt{1806}}{2*168}=\frac{168+4\sqrt{1806}}{336} $
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