4(x-1)=8(x+1)+12

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Solution for 4(x-1)=8(x+1)+12 equation: 



4(x-1)=8(x+1)+12

We move all terms to the left:

4(x-1)-(8(x+1)+12)=0

We multiply parentheses

4x-(8(x+1)+12)-4=0



We calculate terms in parentheses: -(8(x+1)+12), so:

8(x+1)+12

We multiply parentheses

8x+8+12

We add all the numbers together, and all the variables

8x+20

Back to the equation:

-(8x+20)



We get rid of parentheses

4x-8x-20-4=0

We add all the numbers together, and all the variables

-4x-24=0

We move all terms containing x to the left, all other terms to the right

-4x=24

x=24/-4

x=-6

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