4(x-1/2)+42=7(x/7+1)

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Solution for 4(x-1/2)+42=7(x/7+1) equation: 



4(x-1/2)+42=7(x/7+1)

We move all terms to the left:

4(x-1/2)+42-(7(x/7+1))=0

We add all the numbers together, and all the variables

4(+x-1/2)-(7(x/7+1))+42=0

We multiply parentheses

4x-(7(x/7+1))+42-1/2*4=0

We calculate fractions


4x+(-(7(x*2*4)/()+()/()+42=0

We can not solve this equation

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