4(x-2)(x+2)=0

Solution for 4(x-2)(x+2)=0 equation:

Simplifying
4(x + -2)(x + 2) = 0

Reorder the terms:
4(-2 + x)(x + 2) = 0

Reorder the terms:
4(-2 + x)(2 + x) = 0

Multiply (-2 + x) * (2 + x)
4(-2(2 + x) + x(2 + x)) = 0
4((2 * -2 + x * -2) + x(2 + x)) = 0
4((-4 + -2x) + x(2 + x)) = 0
4(-4 + -2x + (2 * x + x * x)) = 0
4(-4 + -2x + (2x + x2)) = 0

Combine like terms: -2x + 2x = 0
4(-4 + 0 + x2) = 0
4(-4 + x2) = 0
(-4 * 4 + x2 * 4) = 0
(-16 + 4x2) = 0

Solving
-16 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 4x2 = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 4x2 = 0 + 16
4x2 = 0 + 16

Combine like terms: 0 + 16 = 16
4x2 = 16

Divide each side by '4'.
x2 = 4

Simplifying
x2 = 4

Take the square root of each side:
x = {-2, 2}