4(x-2)(x-2)+320=0

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Solution for 4(x-2)(x-2)+320=0 equation: 



4(x-2)(x-2)+320=0

We multiply parentheses ..

4(+x^2-2x-2x+4)+320=0

We multiply parentheses

4x^2-8x-8x+16+320=0

We add all the numbers together, and all the variables

4x^2-16x+336=0

a = 4; b = -16; c = +336;
Δ = b2-4ac
Δ = -162-4·4·336
Δ = -5120
Delta is less than zero, so there is no solution for the equation

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