4(x-2)+10=7-5(2x-3)

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Solution for 4(x-2)+10=7-5(2x-3) equation: 



4(x-2)+10=7-5(2x-3)

We move all terms to the left:

4(x-2)+10-(7-5(2x-3))=0

We multiply parentheses

4x-(7-5(2x-3))-8+10=0



We calculate terms in parentheses: -(7-5(2x-3)), so:

7-5(2x-3)

determiningTheFunctionDomain
-5(2x-3)+7

We multiply parentheses

-10x+15+7

We add all the numbers together, and all the variables

-10x+22

Back to the equation:

-(-10x+22)



We add all the numbers together, and all the variables

4x-(-10x+22)+2=0

We get rid of parentheses

4x+10x-22+2=0

We add all the numbers together, and all the variables

14x-20=0

We move all terms containing x to the left, all other terms to the right

14x=20

x=20/14

x=1+3/7

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