4(x-2)+13=(x+3)

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Solution for 4(x-2)+13=(x+3) equation: 



4(x-2)+13=(x+3)

We move all terms to the left:

4(x-2)+13-((x+3))=0

We multiply parentheses

4x-((x+3))-8+13=0



We calculate terms in parentheses: -((x+3)), so:

(x+3)

We get rid of parentheses

x+3

Back to the equation:

-(x+3)



We add all the numbers together, and all the variables

4x-(x+3)+5=0

We get rid of parentheses

4x-x-3+5=0

We add all the numbers together, and all the variables

3x+2=0

We move all terms containing x to the left, all other terms to the right

3x=-2

x=-2/3

x=-2/3

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