4(x-2)+1=3(x+1)-7

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Solution for 4(x-2)+1=3(x+1)-7 equation: 



4(x-2)+1=3(x+1)-7

We move all terms to the left:

4(x-2)+1-(3(x+1)-7)=0

We multiply parentheses

4x-(3(x+1)-7)-8+1=0



We calculate terms in parentheses: -(3(x+1)-7), so:

3(x+1)-7

We multiply parentheses

3x+3-7

We add all the numbers together, and all the variables

3x-4

Back to the equation:

-(3x-4)



We add all the numbers together, and all the variables

4x-(3x-4)-7=0

We get rid of parentheses

4x-3x+4-7=0

We add all the numbers together, and all the variables

x-3=0

We move all terms containing x to the left, all other terms to the right

x=3

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