4(x-2)+3(x-3)=6(x-1)

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Solution for 4(x-2)+3(x-3)=6(x-1) equation: 



4(x-2)+3(x-3)=6(x-1)

We move all terms to the left:

4(x-2)+3(x-3)-(6(x-1))=0

We multiply parentheses

4x+3x-(6(x-1))-8-9=0



We calculate terms in parentheses: -(6(x-1)), so:

6(x-1)

We multiply parentheses

6x-6

Back to the equation:

-(6x-6)



We add all the numbers together, and all the variables

7x-(6x-6)-17=0

We get rid of parentheses

7x-6x+6-17=0

We add all the numbers together, and all the variables

x-11=0

We move all terms containing x to the left, all other terms to the right

x=11

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