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4(x-2)+6=2x+2(1+x)
We move all terms to the left:
4(x-2)+6-(2x+2(1+x))=0
We add all the numbers together, and all the variables
4(x-2)-(2x+2(x+1))+6=0
We multiply parentheses
4x-(2x+2(x+1))-8+6=0
We calculate terms in parentheses: -(2x+2(x+1)), so:We add all the numbers together, and all the variables
2x+2(x+1)
We multiply parentheses
2x+2x+2
We add all the numbers together, and all the variables
4x+2
Back to the equation:
-(4x+2)
4x-(4x+2)-2=0
We get rid of parentheses
4x-4x-2-2=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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