4(x-2)+7x=3(4x-5)

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Solution for 4(x-2)+7x=3(4x-5) equation: 



4(x-2)+7x=3(4x-5)

We move all terms to the left:

4(x-2)+7x-(3(4x-5))=0

We add all the numbers together, and all the variables

7x+4(x-2)-(3(4x-5))=0

We multiply parentheses

7x+4x-(3(4x-5))-8=0



We calculate terms in parentheses: -(3(4x-5)), so:

3(4x-5)

We multiply parentheses

12x-15

Back to the equation:

-(12x-15)



We add all the numbers together, and all the variables

11x-(12x-15)-8=0

We get rid of parentheses

11x-12x+15-8=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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